# Activity

• In the U.S. Army we run the 2mi and I’ve been interested in estimating times for this off others, just like how I try to estimate 100m, 200m, and 400m times. It took me a long while to find out the majority of […] begin{align*} &f(x) = dfrac{1}{1+x^2}end{align*}

Integrating with respect to x from 0 to 1 yields 0.25π. What makes this a guided approach is that this integration range can be […] • begin{align*}& {rm{Given}}:int_0^infty f(x) dx & &(1) : rm{Queen : Property} & &therefore u=(x)^{-1} Longrightarrowint_0^infty f[(x)^{-1}] (x)^{-2} dx & &(2) : rm{Jacksonian : Property} […]

• From the last update I did in regards to my physical fitness I do not believe I have made any progress, if not slightly regressed, and there are reasons for that. I have been quite lazy as of late in regards to […]

• I recently discovered the Fat Free Mass Index a couple of days ago. I actually have to thank the YouTube Algorithm for suggesting another video series by Vitruvian Physique on distinguishing whether or not […]

• I’ve long wondered this question so I thought I’d do some research based on past experiences and information given from various fitness outlets. I stumbled upon a good video by Vitruvian Physique that you can see […]

• begin{align*}& int_0^infty dfrac{1}{(1+x^g)^n} dx =int_0^infty dfrac{(x)^{gn-2}}{(1+x^g)^n} dx & &therefore x^g = t : , : x = t^{frac{1}{g}} Longrightarrowdx = dfrac{t^{frac{1}{g}-1}}{g} dt & […]

• begin{align*}& int_0^{infty} dfrac{1}{(1+x^2)^n} dx & & &{rm{Lemma : (1)}}: int_0^{infty} left[ f(x) right] dx = int_0^{infty} left[ dfrac{f(frac{1}{x})}{(x^2)} right] dx & &{rm{Lemma […]

• 16 April 2019 Formula (19/718 sampled)

begin{align*}rm{200m} &approx rm{100m} left[ 1.997383 + left( dfrac{7.633557}{rm{60m}} right) right] – 11.1841 pm 0.3 & approxrm{100m} left[ 2 + […]

• Context

I was reading through one of the various eBooks by James Gray (How to Become a Philosopher) and I wanted to see if he had written anything on Philosophy in relation to school requirements. It turns out […]

• Let me start off by saying I actually have to thank someone I formerly worked with, Kelly Hernandez. We got into a discussion about UBI, the poor, etc. and from our conversation I discovered this amazing idea. […]

• begin{align*}displaystyle I & = int_{alpha}^{beta} (e)^{x^n} : dx =sum limits_{gamma=0}^infty left[ dfrac{(beta)^{n gamma +1}-(alpha)^{n gamma +1}}{(n gamma +1) (gamma ) !} right]& […]

• Sid … INTJ’s (referred to as “Architects” and “The Master Mind”) are a very rare personality type. They constitute ~ 2.1% of the populace (in regards to males ~3.3%). I fall under the Assertive (A) category of […] • begin{align*}I = displaystyle int_alpha^betadfrac{a(x)^n+b}{cx+d} : dx &=displaystyle dfrac{a}{c} int_alpha^betadfrac{(x)^n+ frac{b}{a}}{x+frac{d}{c}} : dx &=displaystyle dfrac{a}{c} […]

• Walking / Running Calories Burned Based on MET
by C. D. Chester
Using previous data from my article on MET Values to accurately calculate caloric burn (based on weight and other values) I have produced […] • begin{aligned} I = int_0^infty dfrac{1}{(x)^n+1} dx  = dfrac{pi}{nsin{( frac{pi}{n}} )} end{aligned}

begin{aligned} therefore rho=left[ (x)^n+1 right]^{-1} :;: rho mid_0^1 : […]

• So most people know

begin{aligned} 2 times 2 = 4 end{aligned}

and the basic methods taught to us in school using carries (base 10 system), but what if we introduced some calculus just to be a sadist? […]

• The Riemann Zeta Function Using The Pythagorean Theorem
by C. D. Chester
begin{aligned} int_0^infty dfrac{mathrm{e}^{-bx}sinleft(axright)}{a} : dx= dfrac{1}{b^2+a^2} :; a ne 0, b>0 end{aligned}This […] • Zachary Lee
“Obsessed with Integrals” https://philosophicalmath.wordpress.com/
Zachary’s site is very straightforward, unlike the majority of my early work. My earliest work concerned primarily finding […] • I=∫∞01×3+1dx=2π31.5≈1.209199576156145begin{aligned} I=int_0^{infty} frac{1}{x^3+1} ,dx=dfrac{2pi}{3^{1.5}} approx {1.209199576156145} end{aligned}

Partial Fraction Decomposition Method […]